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9(x+2)-8=6x+3(2+x)
We move all terms to the left:
9(x+2)-8-(6x+3(2+x))=0
We add all the numbers together, and all the variables
9(x+2)-(6x+3(x+2))-8=0
We multiply parentheses
9x-(6x+3(x+2))+18-8=0
We calculate terms in parentheses: -(6x+3(x+2)), so:We add all the numbers together, and all the variables
6x+3(x+2)
We multiply parentheses
6x+3x+6
We add all the numbers together, and all the variables
9x+6
Back to the equation:
-(9x+6)
9x-(9x+6)+10=0
We get rid of parentheses
9x-9x-6+10=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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