9(x+3)+3=-7(x-5)-11

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Solution for 9(x+3)+3=-7(x-5)-11 equation: 



9(x+3)+3=-7(x-5)-11

We move all terms to the left:

9(x+3)+3-(-7(x-5)-11)=0

We multiply parentheses

9x-(-7(x-5)-11)+27+3=0



We calculate terms in parentheses: -(-7(x-5)-11), so:

-7(x-5)-11

We multiply parentheses

-7x+35-11

We add all the numbers together, and all the variables

-7x+24

Back to the equation:

-(-7x+24)



We add all the numbers together, and all the variables

9x-(-7x+24)+30=0

We get rid of parentheses

9x+7x-24+30=0

We add all the numbers together, and all the variables

16x+6=0

We move all terms containing x to the left, all other terms to the right

16x=-6

x=-6/16

x=-3/8

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