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9(x+3)+x=3(x+5)+7
We move all terms to the left:
9(x+3)+x-(3(x+5)+7)=0
We add all the numbers together, and all the variables
x+9(x+3)-(3(x+5)+7)=0
We multiply parentheses
x+9x-(3(x+5)+7)+27=0
We calculate terms in parentheses: -(3(x+5)+7), so:We add all the numbers together, and all the variables
3(x+5)+7
We multiply parentheses
3x+15+7
We add all the numbers together, and all the variables
3x+22
Back to the equation:
-(3x+22)
10x-(3x+22)+27=0
We get rid of parentheses
10x-3x-22+27=0
We add all the numbers together, and all the variables
7x+5=0
We move all terms containing x to the left, all other terms to the right
7x=-5
x=-5/7
x=-5/7
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