9(x+3)+x=3(x-7)-8

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Solution for 9(x+3)+x=3(x-7)-8 equation: 



9(x+3)+x=3(x-7)-8

We move all terms to the left:

9(x+3)+x-(3(x-7)-8)=0

We add all the numbers together, and all the variables

x+9(x+3)-(3(x-7)-8)=0

We multiply parentheses

x+9x-(3(x-7)-8)+27=0



We calculate terms in parentheses: -(3(x-7)-8), so:

3(x-7)-8

We multiply parentheses

3x-21-8

We add all the numbers together, and all the variables

3x-29

Back to the equation:

-(3x-29)



We add all the numbers together, and all the variables

10x-(3x-29)+27=0

We get rid of parentheses

10x-3x+29+27=0

We add all the numbers together, and all the variables

7x+56=0

We move all terms containing x to the left, all other terms to the right

7x=-56

x=-56/7

x=-8

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