9(x+3)=3(3x-5)+28

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Solution for 9(x+3)=3(3x-5)+28 equation: 



9(x+3)=3(3x-5)+28

We move all terms to the left:

9(x+3)-(3(3x-5)+28)=0

We multiply parentheses

9x-(3(3x-5)+28)+27=0



We calculate terms in parentheses: -(3(3x-5)+28), so:

3(3x-5)+28

We multiply parentheses

9x-15+28

We add all the numbers together, and all the variables

9x+13

Back to the equation:

-(9x+13)



We get rid of parentheses

9x-9x-13+27=0

We add all the numbers together, and all the variables

14!=0

There is no solution for this equation

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