9(x+3)=3(x+3)+18

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Solution for 9(x+3)=3(x+3)+18 equation: 



9(x+3)=3(x+3)+18

We move all terms to the left:

9(x+3)-(3(x+3)+18)=0

We multiply parentheses

9x-(3(x+3)+18)+27=0



We calculate terms in parentheses: -(3(x+3)+18), so:

3(x+3)+18

We multiply parentheses

3x+9+18

We add all the numbers together, and all the variables

3x+27

Back to the equation:

-(3x+27)



We get rid of parentheses

9x-3x-27+27=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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