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9(x+3)=4(2x+8)
We move all terms to the left:
9(x+3)-(4(2x+8))=0
We multiply parentheses
9x-(4(2x+8))+27=0
We calculate terms in parentheses: -(4(2x+8)), so:We get rid of parentheses
4(2x+8)
We multiply parentheses
8x+32
Back to the equation:
-(8x+32)
9x-8x-32+27=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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