9(x+3)=40-4x

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Solution for 9(x+3)=40-4x equation: 



9(x+3)=40-4x

We move all terms to the left:

9(x+3)-(40-4x)=0

We add all the numbers together, and all the variables

9(x+3)-(-4x+40)=0

We multiply parentheses

9x-(-4x+40)+27=0

We get rid of parentheses

9x+4x-40+27=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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