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9(x+5)-3(x-2)=8+31
We move all terms to the left:
9(x+5)-3(x-2)-(8+31)=0
We add all the numbers together, and all the variables
9(x+5)-3(x-2)-39=0
We multiply parentheses
9x-3x+45+6-39=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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