9(x+5)=5(x-)(3-x)

Solution for 9(x+5)=5(x-)(3-x) equation:

9(x+5)=5(x-)(3-x)

We move all terms to the left:

9(x+5)-(5(x-)(3-x))=0

We add all the numbers together, and all the variables

9(x+5)-(5(+x)(-1x+3))=0

We multiply parentheses

9x-(5(+x)(-1x+3))+45=0

We multiply parentheses ..

-(5(-1x^2+3x))+9x+45=0


We calculate terms in parentheses: -(5(-1x^2+3x)), so:

5(-1x^2+3x)

We multiply parentheses

-5x^2+15x

Back to the equation:

-(-5x^2+15x)


We get rid of parentheses

5x^2-15x+9x+45=0

We add all the numbers together, and all the variables

5x^2-6x+45=0

a = 5; b = -6; c = +45;
Δ = b2-4ac
Δ = -62-4·5·45
Δ = -864
Delta is less than zero, so there is no solution for the equation