9(x+8)+4(x+3)+6=2(x-4)-6

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Solution for 9(x+8)+4(x+3)+6=2(x-4)-6 equation: 



9(x+8)+4(x+3)+6=2(x-4)-6

We move all terms to the left:

9(x+8)+4(x+3)+6-(2(x-4)-6)=0

We multiply parentheses

9x+4x-(2(x-4)-6)+72+12+6=0



We calculate terms in parentheses: -(2(x-4)-6), so:

2(x-4)-6

We multiply parentheses

2x-8-6

We add all the numbers together, and all the variables

2x-14

Back to the equation:

-(2x-14)



We add all the numbers together, and all the variables

13x-(2x-14)+90=0

We get rid of parentheses

13x-2x+14+90=0

We add all the numbers together, and all the variables

11x+104=0

We move all terms containing x to the left, all other terms to the right

11x=-104

x=-104/11

x=-9+5/11

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