9(x-1)(x+8)=2

Solution for 9(x-1)(x+8)=2 equation:

9(x-1)(x+8)=2

We move all terms to the left:

9(x-1)(x+8)-(2)=0

We multiply parentheses ..

9(+x^2+8x-1x-8)-2=0

We multiply parentheses

9x^2+72x-9x-72-2=0

We add all the numbers together, and all the variables

9x^2+63x-74=0

a = 9; b = 63; c = -74;
Δ = b2-4ac
Δ = 632-4·9·(-74)
Δ = 6633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6633}=\sqrt{9*737}=\sqrt{9}*\sqrt{737}=3\sqrt{737}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{737}}{2*9}=\frac{-63-3\sqrt{737}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{737}}{2*9}=\frac{-63+3\sqrt{737}}{18}
$