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9(x-1)-3x=3(12+x)
We move all terms to the left:
9(x-1)-3x-(3(12+x))=0
We add all the numbers together, and all the variables
9(x-1)-3x-(3(x+12))=0
We add all the numbers together, and all the variables
-3x+9(x-1)-(3(x+12))=0
We multiply parentheses
-3x+9x-(3(x+12))-9=0
We calculate terms in parentheses: -(3(x+12)), so:We add all the numbers together, and all the variables
3(x+12)
We multiply parentheses
3x+36
Back to the equation:
-(3x+36)
6x-(3x+36)-9=0
We get rid of parentheses
6x-3x-36-9=0
We add all the numbers together, and all the variables
3x-45=0
We move all terms containing x to the left, all other terms to the right
3x=45
x=45/3
x=15
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