9(x-1)-8(2x-4)=1-8x+x

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Solution for 9(x-1)-8(2x-4)=1-8x+x equation: 


Simplifying
9(x + -1) + -8(2x + -4) = 1 + -8x + x

Reorder the terms:
9(-1 + x) + -8(2x + -4) = 1 + -8x + x
(-1 * 9 + x * 9) + -8(2x + -4) = 1 + -8x + x
(-9 + 9x) + -8(2x + -4) = 1 + -8x + x

Reorder the terms:
-9 + 9x + -8(-4 + 2x) = 1 + -8x + x
-9 + 9x + (-4 * -8 + 2x * -8) = 1 + -8x + x
-9 + 9x + (32 + -16x) = 1 + -8x + x

Reorder the terms:
-9 + 32 + 9x + -16x = 1 + -8x + x

Combine like terms: -9 + 32 = 23
23 + 9x + -16x = 1 + -8x + x

Combine like terms: 9x + -16x = -7x
23 + -7x = 1 + -8x + x

Combine like terms: -8x + x = -7x
23 + -7x = 1 + -7x

Add '7x' to each side of the equation.
23 + -7x + 7x = 1 + -7x + 7x

Combine like terms: -7x + 7x = 0
23 + 0 = 1 + -7x + 7x
23 = 1 + -7x + 7x

Combine like terms: -7x + 7x = 0
23 = 1 + 0
23 = 1

Solving
23 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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