9(x-1)/12=3(x+1)/6

Solution for 9(x-1)/12=3(x+1)/6 equation:

9(x-1)/12=3(x+1)/6

We move all terms to the left:

9(x-1)/12-(3(x+1)/6)=0

We calculate fractions


9x/()+(-(3(x+1)*12)/()=0


We calculate terms in parentheses: +(-(3(x+1)*12)/(), so:

-(3(x+1)*12)/(

We multiply all the terms by the denominator


-(3(x+1)*12)


We calculate terms in parentheses: -(3(x+1)*12), so:

3(x+1)*12

We multiply parentheses

36x+36

Back to the equation:

-(36x+36)


We get rid of parentheses

-36x-36

Back to the equation:

+(-36x-36)


We get rid of parentheses

9x/()-36x-36=0

We multiply all the terms by the denominator


9x-36x*()-36*()=0

We add all the numbers together, and all the variables

9x-36x*()=0