9(x-1)/12=3(x+1)/6

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Solution for 9(x-1)/12=3(x+1)/6 equation:



9(x-1)/12=3(x+1)/6
We move all terms to the left:
9(x-1)/12-(3(x+1)/6)=0
We calculate fractions
9x/()+(-(3(x+1)*12)/()=0
We calculate terms in parentheses: +(-(3(x+1)*12)/(), so:
-(3(x+1)*12)/(
We multiply all the terms by the denominator
-(3(x+1)*12)
We calculate terms in parentheses: -(3(x+1)*12), so:
3(x+1)*12
We multiply parentheses
36x+36
Back to the equation:
-(36x+36)
We get rid of parentheses
-36x-36
Back to the equation:
+(-36x-36)
We get rid of parentheses
9x/()-36x-36=0
We multiply all the terms by the denominator
9x-36x*()-36*()=0
We add all the numbers together, and all the variables
9x-36x*()=0

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