9(x-1)/6=6(x+2)/10

Solution for 9(x-1)/6=6(x+2)/10 equation:

9(x-1)/6=6(x+2)/10

We move all terms to the left:

9(x-1)/6-(6(x+2)/10)=0

We calculate fractions


9x/()+(-(6(x+2)*6)/()=0


We calculate terms in parentheses: +(-(6(x+2)*6)/(), so:

-(6(x+2)*6)/(

We multiply all the terms by the denominator


-(6(x+2)*6)


We calculate terms in parentheses: -(6(x+2)*6), so:

6(x+2)*6

We multiply parentheses

36x+72

Back to the equation:

-(36x+72)


We get rid of parentheses

-36x-72

Back to the equation:

+(-36x-72)


We get rid of parentheses

9x/()-36x-72=0

We multiply all the terms by the denominator


9x-36x*()-72*()=0

We add all the numbers together, and all the variables

9x-36x*()=0