9(x-2)+3=6(x+1)

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Solution for 9(x-2)+3=6(x+1) equation: 



9(x-2)+3=6(x+1)

We move all terms to the left:

9(x-2)+3-(6(x+1))=0

We multiply parentheses

9x-(6(x+1))-18+3=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

9x-(6x+6)-15=0

We get rid of parentheses

9x-6x-6-15=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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