9(x-2)-(3x+1)=7(1-x)

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Solution for 9(x-2)-(3x+1)=7(1-x) equation: 



9(x-2)-(3x+1)=7(1-x)

We move all terms to the left:

9(x-2)-(3x+1)-(7(1-x))=0

We add all the numbers together, and all the variables

9(x-2)-(3x+1)-(7(-1x+1))=0

We multiply parentheses

9x-(3x+1)-(7(-1x+1))-18=0

We get rid of parentheses

9x-3x-(7(-1x+1))-1-18=0



We calculate terms in parentheses: -(7(-1x+1)), so:

7(-1x+1)

We multiply parentheses

-7x+7

Back to the equation:

-(-7x+7)



We add all the numbers together, and all the variables

6x-(-7x+7)-19=0

We get rid of parentheses

6x+7x-7-19=0

We add all the numbers together, and all the variables

13x-26=0

We move all terms containing x to the left, all other terms to the right

13x=26

x=26/13

x=2

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