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9(x-2)-3x=3(x-5)
We move all terms to the left:
9(x-2)-3x-(3(x-5))=0
We add all the numbers together, and all the variables
-3x+9(x-2)-(3(x-5))=0
We multiply parentheses
-3x+9x-(3(x-5))-18=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
6x-(3x-15)-18=0
We get rid of parentheses
6x-3x+15-18=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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