9(x-2)/3=3(x+4)/7

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Solution for 9(x-2)/3=3(x+4)/7 equation: 



9(x-2)/3=3(x+4)/7

We move all terms to the left:

9(x-2)/3-(3(x+4)/7)=0

We calculate fractions


9x/()+(-(3(x+4)*3)/()=0



We calculate terms in parentheses: +(-(3(x+4)*3)/(), so:

-(3(x+4)*3)/(

We multiply all the terms by the denominator


-(3(x+4)*3)



We calculate terms in parentheses: -(3(x+4)*3), so:

3(x+4)*3

We multiply parentheses

9x+36

Back to the equation:

-(9x+36)



We get rid of parentheses

-9x-36

Back to the equation:

+(-9x-36)



We get rid of parentheses

9x/()-9x-36=0

We multiply all the terms by the denominator


9x-9x*()-36*()=0

We add all the numbers together, and all the variables

9x-9x*()=0

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