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9(x-2)/3=3(x+6)/9
We move all terms to the left:
9(x-2)/3-(3(x+6)/9)=0
We calculate fractions
9x/()+(-(3(x+6)*3)/()=0
We calculate terms in parentheses: +(-(3(x+6)*3)/(), so:We get rid of parentheses
-(3(x+6)*3)/(
We multiply all the terms by the denominator
-(3(x+6)*3)
We calculate terms in parentheses: -(3(x+6)*3), so:We get rid of parentheses
3(x+6)*3
We multiply parentheses
9x+54
Back to the equation:
-(9x+54)
-9x-54
Back to the equation:
+(-9x-54)
9x/()-9x-54=0
We multiply all the terms by the denominator
9x-9x*()-54*()=0
We add all the numbers together, and all the variables
9x-9x*()=0
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