9(x-2)/3=6(x+2)/10

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Solution for 9(x-2)/3=6(x+2)/10 equation:



9(x-2)/3=6(x+2)/10
We move all terms to the left:
9(x-2)/3-(6(x+2)/10)=0
We calculate fractions
9x/()+(-(6(x+2)*3)/()=0
We calculate terms in parentheses: +(-(6(x+2)*3)/(), so:
-(6(x+2)*3)/(
We multiply all the terms by the denominator
-(6(x+2)*3)
We calculate terms in parentheses: -(6(x+2)*3), so:
6(x+2)*3
We multiply parentheses
18x+36
Back to the equation:
-(18x+36)
We get rid of parentheses
-18x-36
Back to the equation:
+(-18x-36)
We get rid of parentheses
9x/()-18x-36=0
We multiply all the terms by the denominator
9x-18x*()-36*()=0
We add all the numbers together, and all the variables
9x-18x*()=0

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