9(x-2)/6=3(x+1)/5

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Solution for 9(x-2)/6=3(x+1)/5 equation: 



9(x-2)/6=3(x+1)/5

We move all terms to the left:

9(x-2)/6-(3(x+1)/5)=0

We calculate fractions


9x/()+(-(3(x+1)*6)/()=0



We calculate terms in parentheses: +(-(3(x+1)*6)/(), so:

-(3(x+1)*6)/(

We multiply all the terms by the denominator


-(3(x+1)*6)



We calculate terms in parentheses: -(3(x+1)*6), so:

3(x+1)*6

We multiply parentheses

18x+18

Back to the equation:

-(18x+18)



We get rid of parentheses

-18x-18

Back to the equation:

+(-18x-18)



We get rid of parentheses

9x/()-18x-18=0

We multiply all the terms by the denominator


9x-18x*()-18*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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