9(x-2)/6=3(x-4)/8

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Solution for 9(x-2)/6=3(x-4)/8 equation: 



9(x-2)/6=3(x-4)/8

We move all terms to the left:

9(x-2)/6-(3(x-4)/8)=0

We calculate fractions


9x/()+(-(3(x-4)*6)/()=0



We calculate terms in parentheses: +(-(3(x-4)*6)/(), so:

-(3(x-4)*6)/(

We multiply all the terms by the denominator


-(3(x-4)*6)



We calculate terms in parentheses: -(3(x-4)*6), so:

3(x-4)*6

We multiply parentheses

18x-72

Back to the equation:

-(18x-72)



We get rid of parentheses

-18x+72

Back to the equation:

+(-18x+72)



We get rid of parentheses

9x/()-18x+72=0

We multiply all the terms by the denominator


9x-18x*()+72*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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