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9(x-2)=3(x-4)
We move all terms to the left:
9(x-2)-(3(x-4))=0
We multiply parentheses
9x-(3(x-4))-18=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
9x-3x+12-18=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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