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9(x-2)=8(x-3)+2
We move all terms to the left:
9(x-2)-(8(x-3)+2)=0
We multiply parentheses
9x-(8(x-3)+2)-18=0
We calculate terms in parentheses: -(8(x-3)+2), so:We get rid of parentheses
8(x-3)+2
We multiply parentheses
8x-24+2
We add all the numbers together, and all the variables
8x-22
Back to the equation:
-(8x-22)
9x-8x+22-18=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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