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9(x-3)+3x=-6(x-6)
We move all terms to the left:
9(x-3)+3x-(-6(x-6))=0
We add all the numbers together, and all the variables
3x+9(x-3)-(-6(x-6))=0
We multiply parentheses
3x+9x-(-6(x-6))-27=0
We calculate terms in parentheses: -(-6(x-6)), so:We add all the numbers together, and all the variables
-6(x-6)
We multiply parentheses
-6x+36
Back to the equation:
-(-6x+36)
12x-(-6x+36)-27=0
We get rid of parentheses
12x+6x-36-27=0
We add all the numbers together, and all the variables
18x-63=0
We move all terms containing x to the left, all other terms to the right
18x=63
x=63/18
x=3+1/2
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