9(x-3)+5x=10x-29+2(2x+1)

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Solution for 9(x-3)+5x=10x-29+2(2x+1) equation: 



9(x-3)+5x=10x-29+2(2x+1)

We move all terms to the left:

9(x-3)+5x-(10x-29+2(2x+1))=0

We add all the numbers together, and all the variables

5x+9(x-3)-(10x-29+2(2x+1))=0

We multiply parentheses

5x+9x-(10x-29+2(2x+1))-27=0



We calculate terms in parentheses: -(10x-29+2(2x+1)), so:

10x-29+2(2x+1)

determiningTheFunctionDomain
10x+2(2x+1)-29

We multiply parentheses

10x+4x+2-29

We add all the numbers together, and all the variables

14x-27

Back to the equation:

-(14x-27)



We add all the numbers together, and all the variables

14x-(14x-27)-27=0

We get rid of parentheses

14x-14x+27-27=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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