9(x-3)/3=3(x+3)/7

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Solution for 9(x-3)/3=3(x+3)/7 equation: 



9(x-3)/3=3(x+3)/7

We move all terms to the left:

9(x-3)/3-(3(x+3)/7)=0

We calculate fractions


9x/()+(-(3(x+3)*3)/()=0



We calculate terms in parentheses: +(-(3(x+3)*3)/(), so:

-(3(x+3)*3)/(

We multiply all the terms by the denominator


-(3(x+3)*3)



We calculate terms in parentheses: -(3(x+3)*3), so:

3(x+3)*3

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

-9x-27

Back to the equation:

+(-9x-27)



We get rid of parentheses

9x/()-9x-27=0

We multiply all the terms by the denominator


9x-9x*()-27*()=0

We add all the numbers together, and all the variables

9x-9x*()=0

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