9(x-3)/3=6(x+1)/10

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Solution for 9(x-3)/3=6(x+1)/10 equation: 



9(x-3)/3=6(x+1)/10

We move all terms to the left:

9(x-3)/3-(6(x+1)/10)=0

We calculate fractions


9x/()+(-(6(x+1)*3)/()=0



We calculate terms in parentheses: +(-(6(x+1)*3)/(), so:

-(6(x+1)*3)/(

We multiply all the terms by the denominator


-(6(x+1)*3)



We calculate terms in parentheses: -(6(x+1)*3), so:

6(x+1)*3

We multiply parentheses

18x+18

Back to the equation:

-(18x+18)



We get rid of parentheses

-18x-18

Back to the equation:

+(-18x-18)



We get rid of parentheses

9x/()-18x-18=0

We multiply all the terms by the denominator


9x-18x*()-18*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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