9(x-3)/6=3(x+2)/7

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Solution for 9(x-3)/6=3(x+2)/7 equation: 



9(x-3)/6=3(x+2)/7

We move all terms to the left:

9(x-3)/6-(3(x+2)/7)=0

We calculate fractions


9x/()+(-(3(x+2)*6)/()=0



We calculate terms in parentheses: +(-(3(x+2)*6)/(), so:

-(3(x+2)*6)/(

We multiply all the terms by the denominator


-(3(x+2)*6)



We calculate terms in parentheses: -(3(x+2)*6), so:

3(x+2)*6

We multiply parentheses

18x+36

Back to the equation:

-(18x+36)



We get rid of parentheses

-18x-36

Back to the equation:

+(-18x-36)



We get rid of parentheses

9x/()-18x-36=0

We multiply all the terms by the denominator


9x-18x*()-36*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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