9(x-3)/6=3(x+5)/10

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Solution for 9(x-3)/6=3(x+5)/10 equation: 



9(x-3)/6=3(x+5)/10

We move all terms to the left:

9(x-3)/6-(3(x+5)/10)=0

We calculate fractions


9x/()+(-(3(x+5)*6)/()=0



We calculate terms in parentheses: +(-(3(x+5)*6)/(), so:

-(3(x+5)*6)/(

We multiply all the terms by the denominator


-(3(x+5)*6)



We calculate terms in parentheses: -(3(x+5)*6), so:

3(x+5)*6

We multiply parentheses

18x+90

Back to the equation:

-(18x+90)



We get rid of parentheses

-18x-90

Back to the equation:

+(-18x-90)



We get rid of parentheses

9x/()-18x-90=0

We multiply all the terms by the denominator


9x-18x*()-90*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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