9(x-3)/6=6(x+1)/12

Solution for 9(x-3)/6=6(x+1)/12 equation:

9(x-3)/6=6(x+1)/12

We move all terms to the left:

9(x-3)/6-(6(x+1)/12)=0

We calculate fractions


9x/()+(-(6(x+1)*6)/()=0


We calculate terms in parentheses: +(-(6(x+1)*6)/(), so:

-(6(x+1)*6)/(

We multiply all the terms by the denominator


-(6(x+1)*6)


We calculate terms in parentheses: -(6(x+1)*6), so:

6(x+1)*6

We multiply parentheses

36x+36

Back to the equation:

-(36x+36)


We get rid of parentheses

-36x-36

Back to the equation:

+(-36x-36)


We get rid of parentheses

9x/()-36x-36=0

We multiply all the terms by the denominator


9x-36x*()-36*()=0

We add all the numbers together, and all the variables

9x-36x*()=0