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9(x-3)/6=6(x-2)/2
We move all terms to the left:
9(x-3)/6-(6(x-2)/2)=0
We calculate fractions
9x/()+(-(6(x-2)*6)/()=0
We calculate terms in parentheses: +(-(6(x-2)*6)/(), so:We get rid of parentheses
-(6(x-2)*6)/(
We multiply all the terms by the denominator
-(6(x-2)*6)
We calculate terms in parentheses: -(6(x-2)*6), so:We get rid of parentheses
6(x-2)*6
We multiply parentheses
36x-72
Back to the equation:
-(36x-72)
-36x+72
Back to the equation:
+(-36x+72)
9x/()-36x+72=0
We multiply all the terms by the denominator
9x-36x*()+72*()=0
We add all the numbers together, and all the variables
9x-36x*()=0
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