9(x-3)/6=6(x-2)/2

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Solution for 9(x-3)/6=6(x-2)/2 equation: 



9(x-3)/6=6(x-2)/2

We move all terms to the left:

9(x-3)/6-(6(x-2)/2)=0

We calculate fractions


9x/()+(-(6(x-2)*6)/()=0



We calculate terms in parentheses: +(-(6(x-2)*6)/(), so:

-(6(x-2)*6)/(

We multiply all the terms by the denominator


-(6(x-2)*6)



We calculate terms in parentheses: -(6(x-2)*6), so:

6(x-2)*6

We multiply parentheses

36x-72

Back to the equation:

-(36x-72)



We get rid of parentheses

-36x+72

Back to the equation:

+(-36x+72)



We get rid of parentheses

9x/()-36x+72=0

We multiply all the terms by the denominator


9x-36x*()+72*()=0

We add all the numbers together, and all the variables

9x-36x*()=0

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