9(x-3)=-7(x+2)+27

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Solution for 9(x-3)=-7(x+2)+27 equation: 



9(x-3)=-7(x+2)+27

We move all terms to the left:

9(x-3)-(-7(x+2)+27)=0

We multiply parentheses

9x-(-7(x+2)+27)-27=0



We calculate terms in parentheses: -(-7(x+2)+27), so:

-7(x+2)+27

We multiply parentheses

-7x-14+27

We add all the numbers together, and all the variables

-7x+13

Back to the equation:

-(-7x+13)



We get rid of parentheses

9x+7x-13-27=0

We add all the numbers together, and all the variables

16x-40=0

We move all terms containing x to the left, all other terms to the right

16x=40

x=40/16

x=2+1/2

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