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9(x-3)=2(x-5)-3
We move all terms to the left:
9(x-3)-(2(x-5)-3)=0
We multiply parentheses
9x-(2(x-5)-3)-27=0
We calculate terms in parentheses: -(2(x-5)-3), so:We get rid of parentheses
2(x-5)-3
We multiply parentheses
2x-10-3
We add all the numbers together, and all the variables
2x-13
Back to the equation:
-(2x-13)
9x-2x+13-27=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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