9(x-3)=3(x+4)+19

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Solution for 9(x-3)=3(x+4)+19 equation: 



9(x-3)=3(x+4)+19

We move all terms to the left:

9(x-3)-(3(x+4)+19)=0

We multiply parentheses

9x-(3(x+4)+19)-27=0



We calculate terms in parentheses: -(3(x+4)+19), so:

3(x+4)+19

We multiply parentheses

3x+12+19

We add all the numbers together, and all the variables

3x+31

Back to the equation:

-(3x+31)



We get rid of parentheses

9x-3x-31-27=0

We add all the numbers together, and all the variables

6x-58=0

We move all terms containing x to the left, all other terms to the right

6x=58

x=58/6

x=9+2/3

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