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9(x-3)=5(2x-6)+3
We move all terms to the left:
9(x-3)-(5(2x-6)+3)=0
We multiply parentheses
9x-(5(2x-6)+3)-27=0
We calculate terms in parentheses: -(5(2x-6)+3), so:We get rid of parentheses
5(2x-6)+3
We multiply parentheses
10x-30+3
We add all the numbers together, and all the variables
10x-27
Back to the equation:
-(10x-27)
9x-10x+27-27=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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