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9(x-3)=5(x-5)
We move all terms to the left:
9(x-3)-(5(x-5))=0
We multiply parentheses
9x-(5(x-5))-27=0
We calculate terms in parentheses: -(5(x-5)), so:We get rid of parentheses
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
9x-5x+25-27=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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