9(x-4)+3=4(x+5)+12

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Solution for 9(x-4)+3=4(x+5)+12 equation: 



9(x-4)+3=4(x+5)+12

We move all terms to the left:

9(x-4)+3-(4(x+5)+12)=0

We multiply parentheses

9x-(4(x+5)+12)-36+3=0



We calculate terms in parentheses: -(4(x+5)+12), so:

4(x+5)+12

We multiply parentheses

4x+20+12

We add all the numbers together, and all the variables

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

9x-(4x+32)-33=0

We get rid of parentheses

9x-4x-32-33=0

We add all the numbers together, and all the variables

5x-65=0

We move all terms containing x to the left, all other terms to the right

5x=65

x=65/5

x=13

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