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9(x-4)+6=3(x+2)
We move all terms to the left:
9(x-4)+6-(3(x+2))=0
We multiply parentheses
9x-(3(x+2))-36+6=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
9x-(3x+6)-30=0
We get rid of parentheses
9x-3x-6-30=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6
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