9(x-4)+8=16-3(x+12)

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Solution for 9(x-4)+8=16-3(x+12) equation: 



9(x-4)+8=16-3(x+12)

We move all terms to the left:

9(x-4)+8-(16-3(x+12))=0

We multiply parentheses

9x-(16-3(x+12))-36+8=0



We calculate terms in parentheses: -(16-3(x+12)), so:

16-3(x+12)

determiningTheFunctionDomain
-3(x+12)+16

We multiply parentheses

-3x-36+16

We add all the numbers together, and all the variables

-3x-20

Back to the equation:

-(-3x-20)



We add all the numbers together, and all the variables

9x-(-3x-20)-28=0

We get rid of parentheses

9x+3x+20-28=0

We add all the numbers together, and all the variables

12x-8=0

We move all terms containing x to the left, all other terms to the right

12x=8

x=8/12

x=2/3

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