9(x-4)-7=32-2(x+8)

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Solution for 9(x-4)-7=32-2(x+8) equation: 



9(x-4)-7=32-2(x+8)

We move all terms to the left:

9(x-4)-7-(32-2(x+8))=0

We multiply parentheses

9x-(32-2(x+8))-36-7=0



We calculate terms in parentheses: -(32-2(x+8)), so:

32-2(x+8)

determiningTheFunctionDomain
-2(x+8)+32

We multiply parentheses

-2x-16+32

We add all the numbers together, and all the variables

-2x+16

Back to the equation:

-(-2x+16)



We add all the numbers together, and all the variables

9x-(-2x+16)-43=0

We get rid of parentheses

9x+2x-16-43=0

We add all the numbers together, and all the variables

11x-59=0

We move all terms containing x to the left, all other terms to the right

11x=59

x=59/11

x=5+4/11

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