9(x-4)/3=3(x+2)/7

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Solution for 9(x-4)/3=3(x+2)/7 equation: 



9(x-4)/3=3(x+2)/7

We move all terms to the left:

9(x-4)/3-(3(x+2)/7)=0

We calculate fractions


9x/()+(-(3(x+2)*3)/()=0



We calculate terms in parentheses: +(-(3(x+2)*3)/(), so:

-(3(x+2)*3)/(

We multiply all the terms by the denominator


-(3(x+2)*3)



We calculate terms in parentheses: -(3(x+2)*3), so:

3(x+2)*3

We multiply parentheses

9x+18

Back to the equation:

-(9x+18)



We get rid of parentheses

-9x-18

Back to the equation:

+(-9x-18)



We get rid of parentheses

9x/()-9x-18=0

We multiply all the terms by the denominator


9x-9x*()-18*()=0

We add all the numbers together, and all the variables

9x-9x*()=0

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