9(x-4)/3=3x+12/9

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Solution for 9(x-4)/3=3x+12/9 equation: 


x in (-oo:+oo)

(9*(x-4))/3 = 3*x+12/9 // - 3*x+12/9

(9*(x-4))/3-(3*x)-(12/9) = 0

(9*(x-4))/3-3*x-4/3 = 0

(9*(x-4))/3+(-3*3*x)/3-4/3 = 0

9*(x-4)-3*3*x-4 = 0

-36-4 = 0

-40 = 0

-40/3 = 0

-40/3 = 0 // * 3

-40 = 0

x belongs to the empty set

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