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9(x-5)-4(x-3)=45
We move all terms to the left:
9(x-5)-4(x-3)-(45)=0
We multiply parentheses
9x-4x-45+12-45=0
We add all the numbers together, and all the variables
5x-78=0
We move all terms containing x to the left, all other terms to the right
5x=78
x=78/5
x=15+3/5
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