9(x-5)=-8(4-2x)-6x

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Solution for 9(x-5)=-8(4-2x)-6x equation: 



9(x-5)=-8(4-2x)-6x

We move all terms to the left:

9(x-5)-(-8(4-2x)-6x)=0

We add all the numbers together, and all the variables

9(x-5)-(-8(-2x+4)-6x)=0

We multiply parentheses

9x-(-8(-2x+4)-6x)-45=0



We calculate terms in parentheses: -(-8(-2x+4)-6x), so:

-8(-2x+4)-6x

We add all the numbers together, and all the variables

-6x-8(-2x+4)

We multiply parentheses

-6x+16x-32

We add all the numbers together, and all the variables

10x-32

Back to the equation:

-(10x-32)



We get rid of parentheses

9x-10x+32-45=0

We add all the numbers together, and all the variables

-1x-13=0

We move all terms containing x to the left, all other terms to the right

-x=13

x=13/-1

x=-13

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