9(x-5)=6(x+12)

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Solution for 9(x-5)=6(x+12) equation: 



9(x-5)=6(x+12)

We move all terms to the left:

9(x-5)-(6(x+12))=0

We multiply parentheses

9x-(6(x+12))-45=0



We calculate terms in parentheses: -(6(x+12)), so:

6(x+12)

We multiply parentheses

6x+72

Back to the equation:

-(6x+72)



We get rid of parentheses

9x-6x-72-45=0

We add all the numbers together, and all the variables

3x-117=0

We move all terms containing x to the left, all other terms to the right

3x=117

x=117/3

x=39

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