9(x-6)+6(1-4x)=-16(x+2)-8

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Solution for 9(x-6)+6(1-4x)=-16(x+2)-8 equation:



9(x-6)+6(1-4x)=-16(x+2)-8
We move all terms to the left:
9(x-6)+6(1-4x)-(-16(x+2)-8)=0
We add all the numbers together, and all the variables
9(x-6)+6(-4x+1)-(-16(x+2)-8)=0
We multiply parentheses
9x-24x-(-16(x+2)-8)-54+6=0
We calculate terms in parentheses: -(-16(x+2)-8), so:
-16(x+2)-8
We multiply parentheses
-16x-32-8
We add all the numbers together, and all the variables
-16x-40
Back to the equation:
-(-16x-40)
We add all the numbers together, and all the variables
-15x-(-16x-40)-48=0
We get rid of parentheses
-15x+16x+40-48=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8

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