9(y+1)+6=2(9y+3)

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Solution for 9(y+1)+6=2(9y+3) equation: 



9(y+1)+6=2(9y+3)

We move all terms to the left:

9(y+1)+6-(2(9y+3))=0

We multiply parentheses

9y-(2(9y+3))+9+6=0



We calculate terms in parentheses: -(2(9y+3)), so:

2(9y+3)

We multiply parentheses

18y+6

Back to the equation:

-(18y+6)



We add all the numbers together, and all the variables

9y-(18y+6)+15=0

We get rid of parentheses

9y-18y-6+15=0

We add all the numbers together, and all the variables

-9y+9=0

We move all terms containing y to the left, all other terms to the right

-9y=-9

y=-9/-9

y=1

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